Given:
The vertices of ΔABC are A(-4,4), B(-2,5), and C(-5,2).
The triangle ABC is reflected across the line y-axis to produce the image ΔA'B'C'.
To find:
The coordinates of ΔA'B'C'.
Solution:
If a figure is reflected across the y-axis, then
[tex](x,y)\to (-x,y)[/tex]
Using this rule, we get
[tex]A(-4,4)\to A'(4,4)[/tex]
[tex]B(-2,5)\to B'(2,5)[/tex]
[tex]C(-5,2)\to C'(5,2)[/tex]
Therefore, the vertices of the ΔA'B'C' are A'(4,4), B'(2,5) and C'(5,2).