Answer:
31.96°C
Explanation:
Given that,
Mass of water, m = 100 g
Initial temperature, [tex]T_i=20^{\circ} C[/tex]
The specific heat capacity of water is 4.18 J/(g℃)
We need to find the final temperature of the water if 5000. J of energy is added to the water in the insulated cup.
The heat added to the water is given by :
[tex]Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\\dfrac{Q}{mc}+T_i=T_f\\\\T_f=\dfrac{5000}{100\times 4.18}+20\\\\T_f=31.96^{\circ} C[/tex]
So, the final temperature is 31.96°C.