Question

Find the equation of a line perpendicular to y=-3x-1 that contains the point (-1,1). Write the equation in slope intercept form.

Answer 1

Answer:

y = $\frac{1}{3}$x + 1 $\frac{1}{3}$

Step-by-step explanation:

y = -3x - 1

1. Perpendicular line needs the opposite (reciprocal) of the slope.

             reciprocal of -3 is -1/3, slope 1/3.                    y = 1/3x + b

2. Now find the b (y-intercept).                                     1 = 1/3(-1) + b

                                                                                       1 = -1/3 + b

                                                                                 + 1/3  +1/3

                                                                                    1 1/3 = b

3. Answer         y = $\frac{1}{3}$x + 1 $\frac{1}{3}$