The graph of a function, f is shown above. Let h(x) be defined as
h(x) = (x + 1) · f(x). Find h′(4).

Answer:
A
Step-by-step explanation:
We are given the graph of f and the function:
[tex]h(x)=(x+1)\cdot f(x)[/tex]
And we want to find h'(4).
Therefore, we will differentiate both sides:
[tex]\displaystyle h'(x)=\frac{d}{dx}\Big[(x+1)\cdot f(x)\Big][/tex]
Use the product rule:
[tex]\displaystyle h'(x)=\frac{d}{dx}(x+1)f(x)+(x+1)\frac{d}{dx}[f(x)][/tex]
Differentiate:
[tex]h'(x)=f(x)+(x+1)f'(x)[/tex]
Thus:
[tex]h'(4)=f(4)+(4+1)f'(4)[/tex]
For f'(4), this is the derivative of f at x = 4. We can see that the derivative at this point is -2 as it is a line with a slope of -2.
And using the graph, f(4) is 4.
Therefore:
[tex]h'(4)=4+(5)(-2)=4-10=-6[/tex]
The answer is A.