Frank sights a balloon in the air at an angle of elevation of 66 degree . the horizontal distance from frank to the balloon is 19 feet how far up in the air is the ballon ? (round to the nearest tenth)

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Answer:
42.7 ft
Explanation:
The applicable trig relation is ...
Tan = Opposite/Adjacent
In this geometry, the leg of the right triangle adjacent to the angle of elevation is the horizontal distance to the balloon. The opposite leg is the vertical height of the balloon, which we're being asked to find.
tan(66°) = height/(19 ft)
height = (19 ft)tan(66°) ≈ 42.67 ft
The height of the balloon is about 42.7 feet.