Respuesta :

Given:

The expression is

[tex]\dfrac{12y^3-6y^2}{2y-1}[/tex], where [tex]y\neq \dfrac{1}{2}[/tex].

To find:

The simplified form of the given expression.

Solution:

We have,

[tex]\dfrac{12y^3-6y^2}{2y-1}[/tex]

Taking out the common factors from the numerator, we get

[tex]\dfrac{12y^3-6y^2}{2y-1}=\dfrac{6y^2(2y-1)}{2y-1}[/tex]

Cancel out the common factors from numerator and denominator.

[tex]\dfrac{12y^3-6y^2}{2y-1}=6y^2[/tex]

Therefore, the simplified form of the given expression is [tex]6y^2[/tex].

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