Question

Assuming that $y\neq 1/2,$ simplify the expression$\dfrac{12y^3-6y^2}{2y-1}.$
Please help this is due soon

Answer 1

Given:

The expression is

$\dfrac{12y^3-6y^2}{2y-1}$, where $y\neq \dfrac{1}{2}$.

To find:

The simplified form of the given expression.

Solution:

We have,

$\dfrac{12y^3-6y^2}{2y-1}$

Taking out the common factors from the numerator, we get

$\dfrac{12y^3-6y^2}{2y-1}=\dfrac{6y^2(2y-1)}{2y-1}$

Cancel out the common factors from numerator and denominator.

$\dfrac{12y^3-6y^2}{2y-1}=6y^2$

Therefore, the simplified form of the given expression is $6y^2$.