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If a bowling ball of mass 7.0 kg has a potential energy of 1100 Joules, how high above the ground is the bowling ball?

Respuesta :

Millie627

Answer:

16.03m(2dp)

Explanation:

Ep=m x g x h

1100=7.0x 9.8( gravitational field strength) x h

Height= 1100/7.0 x 9.8

          =16.03498542

          = 16.03m (2dp)

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