Answer:
[tex]x=106[/tex]
Step-by-step explanation:
[tex][Kindly\ find\ the\ attachment\ for\ better\ understanding.]\\We\ are\ given,\\AC\ and\ BD\ are\ two\ parallel\ lines\\\angle CAO=34\\\angle OBD=72\\Lets\ draw\ a\ third\ line\ from\ Point\ O\ parallel\ to\ the\ two\ lines.\\Lets\ denote\ it\ as\ OE.\\\\We\ know\ that,\\'When\ two\ parallel\ lines\ are\ cut\ by\ a\ transversal,\ the\ pairs\ of\ Alternate\\ Interior\ Angles\ formed\ are\ equal'.\\Hence,\\Considering\ parallel\ lines\ AC\ and\ EO,\\\angle CAO=\angle AOE=34\\Similarly,\\[/tex]
[tex]Considering\ parallel\ lines\ EO\ and\ BD,\\\angle EOB = \angle OBD= 72\\Now,\\As\ \angle x\ or \angle AOB=\angle AOE+ \angle EOB,\\\angle x= \angle AOB=34+72=106[/tex]
