AmBeRgAn
AmBeRgAn
27-02-2021
Mathematics
contestada
can anyone help me to solve this question
Respuesta :
firexmxs
firexmxs
27-02-2021
angle x = 57.5°
Step-by-step explanation:
Let say Base of triangle = 2R
Then Radius of circle = R
Area of Semi Circle = (1/2) π R²
Let say Perpendicular height of isosceled triangle = h
then area of triangle = (1/2) * 2R * h
= R * h
R * h = (1/2) π R²
=> h = π R/2
Tan x = h/R
=> Tanx = π R/2R
=> Tanx = π/2
=> Tanx = 3.14/2
=> Tanx = 1.57
=> x = Tan⁻¹(1.57)
=> x = 57.5°
Angle x = 57.5°
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