Answer:
[tex](\frac{13}{16},-\frac{3}{8})[/tex]
Step-by-step explanation:
Midpoint of a segment with the given endpoints [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is defined by,
[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]
In this question endpoints of the segment are,
[tex]Q(-\frac{3}{8},\frac{1}{8})[/tex] and [tex]R(2,-\frac{7}{8})[/tex]
Coordinates of the midpoint will be,
[tex](\frac{-\frac{3}{8}+2}{2},\frac{\frac{1}{8}-\frac{7}{8}}{2})[/tex]
= [tex](\frac{13}{16},-\frac{3}{8})[/tex]
Therefore, coordinates of the midpoint are [tex](\frac{13}{16},-\frac{3}{8})[/tex].
