Question

three consecutive odd integers are such that three times the smallest is 9 more than twice the largest find the three numbers​

Answer 1

Answer:

17, 19, 21

Step-by-step explanation:

let the 3 consecutive odd numbers be n, n + 2 and n + 4 , then

3n = 2(n + 4) + 9 ( 3 times smallest is 9 more than twice the largest )

3n = 2n + 8 + 9

3n = 2n + 17 ( subtract 2n from both sides )

n = 17

n + 2 = 17 + 2 = 19

n + 4 = 17 + 4 = 21

The 3 numbers are 17, 19, 21