mohamdshaheen285
mohamdshaheen285 mohamdshaheen285
  • 27-02-2021
  • Chemistry
contestada

Determine the pH of a 0.001 M solution of a strong acid

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dammyzee
dammyzee dammyzee
  • 27-02-2021

Answer:

ph = 1

Explanation:

[tex]ph = - log_{10}(0.001) [/tex]

[tex] = - log_{10}(1 \times {10}^{ - 1} ) [/tex]

[tex] = - log_{10}( {10}^{ - 1} )[/tex]

[tex]= - ( - 1) log_{10}(10) = 1[/tex]

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