Question

How much pure alcohol should we add to 18 gallons of 35% acid solution to obtain a solution that is 55% alcohol?

Answer 1

Answer:

8 Gallons

Step-by-step explanation:

Answer 2

8 gallons pure alcohol should we add to 18 gallons of 35% acid solution to obtain a solution that is 55% alcohol.

Calculation:

Let the amount of pure alcohol (100%) required be X.

Therefore, 18 gallons at 35% mixed with X gallons at 100% will give (X + 18) gallons at 55% of alcohol.

It means, 18×35 + X×100 = (X +18) ×55

630 + 100X = 55X + 990

100X - 55X = 990 - 630

45X = 360

X = 360 ÷ 45

X = 8 gallons

Which alcohol is consider as pure alcohol?

An ethanol is a an alcohol which is consider as pure alcohol with molecular formula C2H6OH.

To learn more about pure alcohol here.

https://brainly.com/question/21440134

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