Question

a. A student builds a simple circuit with a single resistor with resistance R and measures an electric potential difference ΔV across the resistor. Then, the student replaces the resistor with a new one of resistance 2R and keeps the electric potential difference the same. What is the current (I2) through the new circuit in terms of the original current​

Answer 1

Answer:

The new current is half the original current.

Step-by-step explanation:

Ohm's Law:

We use Ohm's law to solve this question. It states that

$\Delta_V = RI$

In which $\Delta_V$ is the voltage difference, R is the resistence, and I is the current.

A student builds a simple circuit with a single resistor with resistance R and measures an electric potential difference ΔV across the resistor.

So

$\Delta_V = RI_{1}$

$I_{1} = \frac{\Delta_V}{R}{/tex]

Then, the student replaces the resistor with a new one of resistance 2R and keeps the electric potential difference the same.

Now the current will be

[tex]\Delta_V = 2RI_{2}$

$I_{2} = \frac{\Delta_V}{2R} = \frac{1}{2}(\frac{\Delta_V}{R}) = \frac{1}{2}(I_1)$

The new current is half the original current.