Answer:
16 cm^2
Step-by-step explanation:
Given
[tex]\triangle CAE[/tex] -- Bigger Triangle
[tex]\triangle CBD[/tex] -- Smaller Triangle
[tex]k = \frac{4}{3}[/tex] --- Scale factor
Area of CBD = 9
Required
Determine the area of CAE
The area of triangle CBD is:
[tex]A_1 = \frac{1}{2}bh[/tex]
[tex]\frac{1}{2}bh = 9[/tex]
The area of CAE is:
[tex]A_2 = \frac{1}{2}BH[/tex]
Where:
[tex]B = \frac{4}{3}b[/tex] and
[tex]H = \frac{4}{3}h[/tex]
The above values is the dimension of the larger triangle (after dilation).
So, we have:
[tex]A_2 = \frac{1}{2}*\frac{4}{3}b * \frac{4}{3} * h[/tex]
[tex]A_2 = \frac{1}{2}*\frac{4}{3} * \frac{4}{3} *b* h[/tex]
[tex]A_2 = \frac{1}{2}*\frac{16}{9} *b* h[/tex]
Re-order
[tex]A_2 = \frac{16}{9}*\frac{1}{2}* b* h[/tex]
[tex]A_2 = \frac{16}{9}*\frac{1}{2}bh[/tex]
Recall that:
[tex]\frac{1}{2}bh = 9[/tex]
[tex]A_2 = \frac{16}{9}*9[/tex]
[tex]A_2 = 16[/tex]
Hence, the area is 16 cm^2