Answer:
The correct answer is -
1. 25%
2. 75%
3. 1:2:1
Explanation:
It is given that slimy snort S is dominant over stringy snort s which means in case, of heterozygous the slimy snort will be expressed only.
The cross between Ss and Ss will produce gametes S, sand S, s.
then,
S s
S SS Ss
s Ss ss
From the given punnett, it is clear that there are 1 stringy snort offspring and three slimy snort offspring will be produced which means, there is 25% likelihood of stringy snort and 75% likelihood of slimy snort.
Genotypically there are 1 dominant: 2 heterozygous : 1 recessive present.
