Answer:
[tex]\displaystyle d = \sqrt{61}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Algebra I
Algebra II
- Distance Formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Step-by-step explanation:
Step 1: Define
Point P1(0, 0)
Point P2(5, 6)
Step 2: Identify
x₁ = 0, y₁ = 0
x₂ = 5, y₂ = 6
Step 3: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d
- Substitute in points [Distance Formula]: [tex]\displaystyle d = \sqrt{(5-0)^2+(6-0)^2}[/tex]
- [Distance] [√Radical] (Parenthesis) Subtract: [tex]\displaystyle d = \sqrt{(5)^2+(6)^2}[/tex]
- [Distance] [√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{25+36}[/tex]
- [Distance] [√Radical] Add: [tex]\displaystyle d = \sqrt{61}[/tex]