Question

The volume occupied by 12.5 moles of nitrogen gas at STP is liters.​

Answer 1

Answer:

280 Liters

Explanation:

1 mole is equal to 22.4 L at STP, so you can use the equation:

12.5 moles * 22.4 L

to find out how many liters.

Answer 2

The volume occupied by 12.5 moles of nitrogen gas at STP is 280 Liters.

The given parameters;

• number of moles of the gas, n = 12.5 moles
• I mole of gas at stp = 22.4 L

The volume of occupied by the nitrogen gas at stp is calculated by comparing the given number of moles to 1 moles of at standard condition (stp), as shown below;

1 moles of gas --------------- 22.4 L

12.5 moles of gas ------------ ?

= 12.5 x 22.4

= 280 L.

Thus, the volume occupied by 12.5 moles of nitrogen gas at STP is 280 Liters.

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