Answer:
1. [tex]3 : 2 = H : C[/tex]
2. [tex]2 : 3 = C : H[/tex]
3. [tex]2 : 2 = O : T[/tex]
4. [tex]13 : 3 = All\ Letters : H[/tex]
5. [tex]2 : 13 = E : All\ Letters[/tex]
Step-by-step explanation:
See comment for complete question.
We have the following letters and their frequencies
[tex]C = 2[/tex] [tex]H = 3[/tex] [tex]A = 2[/tex] [tex]T = 2[/tex] [tex]O = 2[/tex] [tex]E = 2[/tex]
Solving (1): 1. [tex]3 : 2 = H : [\ ][/tex]
From the alphabets listed above:
[tex]H = 3[/tex], [tex]C = 2[/tex] [tex]A = 2[/tex] [tex]T = 2[/tex] [tex]O = 2[/tex] [tex]E = 2[/tex]
So, the 3:2 can be H : any of the alphabets. For this solution, we use:
[tex]3 : 2 = H : C[/tex]
Solving (2) [tex]2 : 3 = [\ ] : H[/tex]
This is the inverse of (1) solved above.
So 2 : 3 is:
[tex]2 : 3 = C : H[/tex]
Solving (3) [tex]2 : 2 = O : [\ ][/tex]
From the alphabets listed above:
[tex]C = 2[/tex] [tex]A = 2[/tex] [tex]T = 2[/tex] [tex]O = 2[/tex] [tex]E = 2[/tex]
Any selected alphabet will represent 2 : 2
So, we have:
[tex]2 : 2 = O : T[/tex] or O : any of C, A and E
Solving (4):. [tex]13 : 3 = [\ ] : H[/tex]
The total of all alphabet in the given word is: 13.
So,
[tex]13 : 3 = All\ Letters : H[/tex]
Solving (5): [tex]2 : 13 = E : [\ ][/tex]
The total of all alphabet in the given word is: 13.
So,
[tex]2 : 13 = E : All\ Letters[/tex]