Respuesta :
Answer:
- -3x² + 6x - 4
Step-by-step explanation:
Simplify:
- 4x + 7 - 8x² + 2x + 5x² - 11 =
- x²(-8 + 5) + x(4 + 2) + (7 - 11) =
- -3x² + 6x - 4
Answer:
[tex] \tt \huge \boxed{ \boxed{\color{silver} { - 3x}^{2} + 6x - 4}}[/tex]
Step-by-step explanation:
to understand this
you need to know about:
- algebra
- algebraic addition subtraction
- PEMDAS
tips and formulas:
- quadratic expression standard form:ax²+bx+c
- order of PEMDAS
- parentheses
- exponent
- multiplication or
- division
- addition
- subtraction
- left to right
given:
- 4x+7-8x²+2x+5x²-11
to do
- simplification
let's do:
[tex]step - 1 : define[/tex]
[tex] \sf 4x + 7 - {8x}^{2} + 2x + {5x}^{2} - 11[/tex]
[tex]step - 2 : simplify[/tex]
- [tex] \tt \: rewrite : \\ \sf {8x}^{2} + {5x}^{2} + 4x + 2x + 7 - 11[/tex]
- [tex] \tt \:combine \: like \: terms: \\ \sf { - 3x}^{2} + 6x + 7 - 11[/tex]
- [tex] \tt \: substrak : \\ \sf { - 3x}^{2} + 6x - 4[/tex]
therefore
we can see the expression is in standard form since a,b and c is -3,6 and -4
also let's justify it
substitute the value of a,b and c respectively
(-3)x²+(6)x+(-4)
-3x²+6x-4 (proven)