Question

one number is 7 more than another and its square is 77 more than the square of the smaller numbers. what are the numbers ? ​

Answer 1

Answer:

2 and 9

Explanation:

x = y + 7

x^2 = y^2 + 77

Substitute x = y + 7 into the second equation

(y+7)^2 = y^2 + 77

y^2 + 14y + 49 = y^2 + 77

14y + 49 = 77

14y = 28

y = 2

x = y +7, y=2

x = 2 + 7

x = 9