Question

2) A student determined the melting point of a substance to be 55.2DC. If the accepted value
is 50.1C, what is the percent error in the student's determination?
A) 12.0 B) 5.10 C) 10.2 D) 9.24

Answer 1

Answer:

C) 10.2

Explanation:

Formula: Actual-Expected/Expected

The actual was 55.2 while the expected was 50.1

55.2-50.1/50.1=0.101796407 * 100= 10.2%

Answer 2

The percentage error in the student's determination is 10.2%

The correct answer to the question is Option C. 10.2

From the question given above, the following data were obtained:

Measured value = 55.2 °C

Accepted value = 50.1 °C

Percentage error =?

Next, we shall determine the absolute error. This can be obtained as follow:

Measured value = 55.2 °C

Accepted value = 50.1 °C

Absolute error =?

Absolute error = |Measured – Accepted|

Absolute error = |55.2 – 50.1|

Absolute error = 5.1

Finally, we shall determine the percentage error.

Absolute error = 5.1 °C

Accepted value = 50.1 °C

Percentage error =?

$Percentage error = \frac{Absolute error }{Accepted value} * 100\\\\= \frac{5.1}{50.1} * 100$

Percentage error = 10.2%

Therefore, the percentage error in the student's determination is 10.2%.

The correct answer to the question is Option C. 10.2

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