Question

If a = 2 and b = 3, then the value of (a^b + b^a)-1 is :​

Answer 1

Answer:

$16$

Step-by-step explanation:

Substituting $a=2$ and $b=3$ into $(a^{b}+b^{a})-1$ gives us:

$(a^{b}+b^{a})-1$

$=(2^{3} +3^{2})-1$ (Substitute given values into expression)

$=(8+9)-1$ (Evaluate exponents)

$=17-1$ (Evaluate expression in parentheses)

$=16$ (Simplify)

Hope this helps!

Answer 2

Answer:

16

Step-by-step explanation:

Given

($a^{b}$ + $b^{a}$ ) - 1 ← substitute a = 2, b = 3

= (2³ + 3²) - 1

= (8 + 9) - 1

= 17 - 1

= 16