Question

$x {}^{2} - 2x + 8 = 0$
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Answer 1

SOLVE THE QUADRATIC EQUATION

Answer:

$x = 1 + \sqrt{7} i \\ x = 1 - \sqrt{7} i$

Explanation:

$x {}^{2} - 2x + 8 = 0$

$(x - 1) {}^{2} + 8 - 1 {}^{2} = 0$

$(x - 1) {}^{2} = 8 - 1 {}^{2} = 0$

$(x - 1) {}^{2} = - 8 + 1 {}^{2}$

$(x - 1) {}^{2} = - 8 + 1$

$(x - 1) {}^{2} = - 7$

x - 1 = ± √-7

x = ±√7i + 1

$x = 1 + \sqrt{7} i \\ x = 1 - \sqrt{7} i$

Answer 2

Oh someone already answered:(