Question

A person invested $7, 400 in an account growing at a rate allowing the money to
double every 6 years. How much money would be in the account after 4 years, to the
nearest dollar?

Answer 1

Answer:

$11747

Step-by-step explanation:

$m=7400x^{t} \\2*7400=7400x^{6}\\x=1.122\\t=4\\m=7400*1.122^{4} =11747$