Question

A submarine travels 12 km due West from its base and then turns and travels due South for 14.8 km. How far away is the submarine from its base? .

Answer 1

Answer:

the submarine travels 26.8 km. from its base

Answer 2

Answer:

The answer is 19.1

Step-by-step explanation:

$z = \sqrt{ {x}^{2} + {y}^{2} } = \sqrt{ {12}^{2} + {14.8}^{2} } = 19.1$