Answer:
Answer:
x + 2y - 3 = 0
Step-by-step explanation:
Coordinates of the points P and Q are (-3, 0) and (0, 6) respectively.
Slope of PQ = (0- 6)/(-3 - 0) = - 6/-3 = 2
Slope of line perpendicular to PQ = - 1/2
Since, required line passes through point R(7, - 2) and is perpendicular to PQ.
Therefore, equation of line in point slope form is given as:
\begin{gathered}y - (-2) = - \frac{1}{2} (x - 7) \\ \\ y + 2 = - \frac{1}{2} (x - 7) \\ \\2(y + 2) = - (x - 7) \\ \\ 2y + 4 = - x + 7 \\ \\ 2y + 4 + x - 7 = 0 \\ \\ x + 2y - 3 = 0\end{gathered}
y−(−2)=−
2
1
(x−7)
y+2=−
2
1
(x−7)
2(y+2)=−(x−7)
2y+4=−x+7
2y+4+x−7=0
x+2y−3=0
Therefore x + 2y - 3 = 0 is the required equation of line.
hope it helps you
