Question

PLEASE HELP ME> A proton travels at right angles through a magnetic field of 0.025 teslas. If the magnitude of the magnetic force on the proton is 1.8 × 10-14 newtons, what is the velocity of the proton? The value of q = 1.6 × 10-19 coulombs.

A. 1.8 × 105 meters/second
B. 1.8 × 106 meters/second
C. 2.5 × 106 meters/second
D. 3.8 × 106 meters/second
E. 4.5 × 106 meters/ second

Answer 1

F = Bqv so v = F / (Bq)

v = 1.8x10-14 / (0.025*1.6x10-19)

v = 4.5x10^6 metres/second

So the answer is E.

Answer 2

E is the Answer hope this helps