Question

A water lily is floating in a murky pond rooted on the bottom of the pond by a stem of unknown length. The lily can be lifted 2 feet over the water and moved 6 feet to the side. What is the depth of the pond?

Answer 1

12 Feet is the depth of the pond.  I am just guessing but i think that is it.

Answer 2

The depth of the pond is 8 feet and this can be determined by using the Pythagorean theorem.

Given :

• A water lily is floating in a murky pond rooted on the bottom of the pond by a stem of unknown length.
• The lily can be lifted 2 feet over the water and moved 6 feet to the side.

The Pythagorean theorem can be used to determine the depth of the pound. The Pythagorean theorem according to the attached diagram is given by:

$\rm (BD)^2 = (BC)^2+(CD)^2$

Now, put the value of the given lengths according to the attached diagram in the above equation.

$(x+2)^2= 6^2+x^2$

$x^2+4+4x = 36+x^2$

4x = 32

x = 8

Therefore, the depth of the pond is 8 feet.

For more information, refer to the link given below:

https://brainly.com/question/15190643