Question

Find the zero of y=x^2+6x-4 by completing the square

Answer 1

x^2 + ( 6/2 )^2 - ( 6/2 )^2 - 4 = 0
( x + 3 )^2 - 3 - 4 = 0
( x + 3 )^2 - 7 = 0