A student used a DCP solution (standardized to 9.98x10-4M) to analyze a sample of extract from 2.50g of solid food. The titration required 22.49mL of DCP. 87.00% of all the ascorbic acid in the food was collected in the extract. (MM Ascorbic Acid = 176.124 g/mol)
What mass of food (in grams) would be required to attain the RDA of ascorbic acid (60 mg)
Given that the molarity of DCP equals 9.98x10-4M. And it
used to analyze a sample of extract from 2.50g of solid food. The titration
required 22.49mL of DCP. 87.00% of all the ascorbic acid in the food was
collected in the extract.
Amount of solid = 60 mg AA (100mg/87mg)(1g/1000mg)(1 mol
AA/176.124 gAA)(1mol DPC/1mol AA)( 1L DCP/9.98x10-4mol DPC)(2.50g solid/0.02249
L DPC) = 43.6 g solid.
