Question

What are the solutions of 2x2 3x = -5?

Answer 1

I'm guessing the equation is 2x^2-3x=-5
If this is the case, then you need to set the equation to equal 0 by moving the -5 to the left side of it
2x^2-3x+5=0
The you can factor the equation
(2x-5)(x+1)=0
now solve for each factor
2x-5=0 is x=5/2x
x+1=0 is x=-1

Answer 2

Your answer is:::

-3 + i  √31 over 4

OR

-3 - i √31 over 4