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A spring has a natural length of 25 meters. A force of 12 newtons is required to stretch the spring to a length of 30 meters. How much work is done to stretch the spring from it's natural length to 40 meters?

Respuesta :

F = ks 
12 = k(15) 

12/15 = k 


integrating from 0 to 15 
12/15 sds 


12/15 x S squared / 2 from 0 to 15 

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