Question

x-1/x^2 - x - 20 Give the equivalent numerator if the denominator is (X - 5)(x + 4)(x + 3)
x^2 + 2x + 3
x^2 + 2x - 3
x^2-3​

Answer 1

Answer:

$x^2+2x-3$

Step-by-step explanation:

Note that $x^2-x-20=(x-5)(x+4)$, so, if the denominator is $(x-5)(x+4)(x+3)$, we need to multiply the numerator by $(x+3)$. And $(x-1)(x+3)=x^2+2x-3$.