Question

How many liters of a 10% solution should be mixed with 60 liters of a 25% solution to
get a 15% solution?

Answer 1

Answer:

120 liters of the 10% solution should be mixed with 60 liters of a 25% solution to  get a 15% solution.

Step-by-step explanation:

Let 'x' be the quantity of 10% solution

Given that we need determine many liters of a 10% solution should be mixed with 60 liters of a 25% solution to  get a 15% solution.

As

10% of x = 0.1x

60 liters of a 25%  = 60 × 0.25

Thus,

The equation becomes

$0.1x+60\times \:0.25=0.15\left(x+60\right)$

Multiply both sides by 100  

$0.1x\times \:100+15\times \:100=0.15\left(x+60\right)\times \:100$  

$10x+1500=15\left(x+60\right)$

$10x+1500=15x+900$

Subtract 1500 from both sides

$10x+1500-1500=15x+900-1500$

Simplify

$10x=15x-600$

Subtract 15x from both sides

$10x-15x=15x-600-15x$

Simplify

$-5x=-600$

Divide both sides by -5

$\frac{-5x}{-5}=\frac{-600}{-5}$

Simplify

$x=120$

Therefore,

• 120 liters of the 10% solution should be mixed with 60 liters of a 25% solution to  get a 15% solution.