Mass of Aluminum = 157.5 g
Given
17.5 g of Hydrogen
Required
Mass of Aluminum
Solution
Reaction
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
mol Hydrogen :
= mass : molar mass
= 17.5 g : 2 g/mol
= 8.75
From the equation, mol Al :
= 2/3 x mol H₂
= 2/3 x 8.75
= 5.83
Mass Al :
= 5.83 x 27 g/mol
= 157.5 g
