Question

A 33 kg child on a swing has a potential energy of 720 J with respect to the ground. What is the child’s height above the ground? please answer soon

Answer 1

Answer:

h = 2.22 m

Explanation:

Using the international system, we know that the gravity of the earth is 9.8 m / s².

then, we have as data:

• Potential Energy (Ep) = 720 J
• Mass (m) = 33 kg
• Gravity (g) = 9.8 m/s²
• Height (h) = ?

Use formula:

• $\boxed{h=\frac{Ep}{m*g}}$

Replace:

• $\boxed{h=\frac{720J}{33kg*9.8\frac{m}{s^{2}}}}$

Joules descompose:

• $\boxed{h=\frac{720N*m}{33kg*9.8\frac{m}{s^{2}}}}$

Solve the multiply of mass and gravity:

• $\boxed{h=\frac{720N*m}{323.4kg*\frac{m}{s^{2}}}}$

Multiply the units. Knowing that kg * m/s² = N, so:

• $\boxed{h=\frac{720N*m}{323.4N}}}$

Simplify the Newtons (N), and it divides:

• $\boxed{h=2.22\ m}$

What is the child’s height above the ground?

The child's height above the ground is 2.22 meters.