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You have a car traveling 10m/s that speeds up to 40m/s. If it takes 4 seconds, how far does it travel during that time

Respuesta :

Answer:

d = 100 m

Explanation:

Given that,

Initial speed of a car, u = 10 m/s

Final speed of a car, v = 40 m/s

Time, t = 4 seconds

We need to find how far does it travel during that time. Let the car travel d distance. We can find it using third equation of motion as follows :

[tex]v^2-u^2=2ad[/tex] ...(1)

a is acceleration and d is the distance

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{40-10}{4}\\\\a=7.5\ m/s^2[/tex]

So, equation (1) becomes,

[tex]d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(40)^2-(10)^2}{2\times 7.5}\\\\d=100\ m[/tex]

So, it will travel 100 m during that time.