Question

CuBr(s)⇄Cu+(aq)+Br−(aq)

Shown above is the chemical equation for the dissolution of the slightly soluble salt CuBr(s). Its Ksp value in pure water was experimentally determined. CuBr was found to be much less soluble in a 0.001MNaBr solution than in pure water. Which of the following correctly explains the decrease in solubility of CuBr in 0.001 M NaBr?

A.)The concentration of water is much less in the NaBr solution than in pure water, reducing the rate of dissolution of the salt.
B.)The presence of Na+ ions in the solution inhibits the dissolution of salts.
C.)The presence of additional Br− already in the solution decreases the value of the Ksp for CuBr , causing the solubility to decrease.
D.)The presence of additional Br− ions already in the solution means equilibrium will be reached when much less CuBr has dissolved.

Answer 1

Answer:

D) The presence of additional Br- ions already in the solution means equilibrium will be reached when much less CuBr has dissolved.

Explanation:

CuBr ⇄ $Cu^+$ + $Br^-$

Because there is Br- in CuBr, when put into solution, those Br- ions become part of the products side of the equation, shifting the equilibrium back towards the CuBr side, meaning less CuBr will dissolve.

Answer 2

The decrease in the solubility of the CuBr in NaBr solution has been due to the presence of additional Br ions in the solution. Thus option C is correct.

The equilibrium position has been the condition when the concentration of the reactants and products has been equal. The solubility of the CuBr has been dependent on the ksp for the solution.

The ksp has been the solubility product and has been dependent on the concentration of the reactants. The NaBr solution will be dissociated in the form of Na ions and Br ions. The dissolution has been based on the equilibrium of the CuBr.

With the presence of additional Br ions, the equilibrium of the CuBr solution has been reached earlier, and thereby the solubility of the solution has been decreased.

The decrease in the solubility of the CuBr in NaBr solution has been due to the presence of additional Br ions in the solution. Thus option C is correct.

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