Answer:
Q = - 18830.9 J
Explanation:
Given data:
Mass of water = 85 g
Initial temperature = 55°C
Final temperature = 2°C
Amount of heat lost = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water 4.18 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 2°C - 55°C
ΔT = -53°C
Q = 85 g × 4.18 j/g.°C × -53°C
Q = - 18830.9 J
Negative sign shows that heat is released.
