C = 84.71%
H = 5.88%
O = 9.41%
Given
3-phenylphenol, C12H10O
Required
The mass percent
Solution
Ar C = 12 g/mol
Ar H = 1 g/mol
Ar O = 16 g/mol
MW C12H10O = 170 g/mol
The mass percent :
C = (12x12/170) x 100%
C = 84.71%
H = (10x1)/170) x 100%
H = 5.88%
O = (1 x 16)/170 x 100%
O = 9.41%