Question

For the balanced equation shown below, if the reaction theoretically
should produce 7.99g CaO but experimentally produces 6.81 grams of
CaO, what is the percent yield?
CaCO3---->CaO+CO2
85.23%
0 14.77%
54.41%
O 117.33%

Answer 1

Answer:

Percent yield = 85.23%

Explanation:

Given data:

Theoretical yield = 7.99 g

Actual yield = 6.81 g

Percent yield of CaO = ?

Solution:

Formula:

Percent yield = ( actual yield / theoretical yield ) × 100

by putting values,

Percent yield = (6.81 g/ 7.99 g) × 100

Percent yield = 0.8523× 100

Percent yield = 85.23%