Question

At what temperature would 2.10 moles of Nitrogen gas have a pressure of 1.25 atm and in a 25.0 L tank? (Hint: R = 0.082 L atm K−1 mol−1)

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Answer 1

Given :-

• Moles = 2.10

• Gas = Nitrogen

• Pressure = 1.25 atm

• Volume = 25L

To Find :-

• Temperature

Solution :-

As we know that

PV = nRT

Here,

• P = Pressure
• V = Volume
• n = Moles
• T = Temperature

According to the question,

• 1.25 × 25 = 2.1 × 0.082 × T
• 31.25 = 2.1 × 0.082 × T
• 31.25 = 1.722T
• 31.25/0.1722 = T
• 181 ≈ T

Temperature is 181 K

• $\large\fbox{181 K}$