A projectile is fired straight up from an initial height of 210 feet, and its height is a function of time, h(t) = -167 + 128t + 210
where h is the height in feet and t is the time in second with t = 0 corresponding to the instant it launches. What is the height 5
seconds after launch? Be sure to include units of measurement.
Something feels off about that equation. In linear form, the projectile would continue up infinitely. You sure it wasn't supposed to be h(t) = -167t^2 + 128t + 210?
