Question

A 2.0 L flexible container holds 5.0 moles of oxygen (O2) gas. An additional 15.0 moles of nitrogen gas (N2) is added to the container. What is the new volume of the container?
a. 8.0 L
b. 0.13 L
c. 0.50 L
d. 6.0L

Answer 1

Answer 8.0 L.

2.0L / 5.0 moles = x / 20.0 => x = 20 / 5 * 2 = 8

Answer 2

The  new  volume of the container is 8.0 L

 calculation

total  volume=    volume of  O2 +  volume of N2

 volume of  O2 =  2.0 l

find the volume of N2  which is calculated as below

if 2.0 L  =  5.0 moles

   ?  L  = 15.0  moles

by cross multiplication

= (15.0 moles  x  2.0 L) / 5.0 mole = 6.0 L

total volume ( new volume ) =  6.0 L +  2.0 L = 8.0 L