Question

Question 3 of 10
The slope of the line below is 4. Which of the following is the point-siope form
of the line?
A. y- 4 = 4(x-3)
B. y+ 4 = 4(x + 3)
C. y+ 4 = 4(x+3)
Dy-4--4(x-3)

Answer 1

Answer:

The point-slope form  of the line is:

$y + 4 = 4(x+3)$

Hence, option B is correct.

Step-by-step explanation:

We know the point-slope form of the line equation is

$y-y_1=m\left(x-x_1\right)$

where

• m is the slope of the line

• (x₁, y₁) is the point

Given

The slope m = 4

From the graph, we can take the point (-3, -4)

So, in our case:

(x₁, y₁) = (-3, -4)

m = 4

now substituting m = 4 and (x₁, y₁) = (-3, -4) in the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

$y - (-4) = 4(x - (-3))$

$y + 4 = 4(x+3)$

Therefore, the point-slope form  of the line is:

$y + 4 = 4(x+3)$

Hence, option B is correct.

• The graph of the line is also attached.