Question

3. A sample of neon gas has a volume of 1.2 L at 28.5°C. What will the volume be at 125°C it the
pressure remains constant?

Answer 1

Answer:

1.58L

Explanation:

Given parameters:

Initial volume  = 1.2L

Initial temperature  = 28.5°C  = 28.5 + 273  = 301.5K

Final temperature  = 125°C  = 125 + 273  = 398K

Unknown:

New volume  = ?

Solution:

Volume and temperature relationship is resolved using the Charles's law.

The law states that "the volume of a fixed mass of a gas varies directly as its absolute temperature if the the pressure is constant".

So;

       $\frac{V1}{T1}$    = $\frac{V2}{T2}$  

V1 is the initial volume

T1 is the initial temperature

V2 is the new volume

T2 is the new temperature

             $\frac{1.2}{301.5}$    = $\frac{V2}{398}$    

              301.5V2  = 477.6

                       V2  = 1.58L