The mole fraction of sulfuric acid : 0.073
Given
3.75 M sulfuric acid solution that has density of 1.230 g/mL
Required
The mole fraction
Solution
3.75 M = 3.75 mol/L
For 1 L solution :
mass of solution = 1230 g
mass Sulfuric acid : 3.75 mol x 98 g/mol=367.5 g
mass water = 1230-367.5 = 862.5 g
mol water = 862.5 : 18 g/mol= 47.92
mol total = 3.75 + 47.92 = 51.67
mole fraction of sulfuric acid :
= 3.75 : 51.67
= 0.073