The value of k is "8".
Find K:
[tex](6x+k)(3x-11)=0\ \ is \ \ 1 \\\\K=?[/tex]
[tex]\to (6x+k)(3x-11)=0 \ \ is \ \ 1 \\\\\to (6x+k)=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ and \ \ \ \ \ \ \ \ \ \ \ \ \ \ (3x-11)=0\\\\\to 6x=-k\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ and \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3x=11\\\\\to x=-\frac{k}{6}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ and \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=\frac{11}{3}\\\\[/tex]
[tex]\to - \frac{k}{6}+ \frac{11}{3}=1\\\\\to \frac{-2k+ 22}{6}=1\\\\\to -2k+ 22=6\\\\\to -2k =6-22\\\\\to -2k =-16\\\\\to k=\frac{16}{2}\\\\\to k=8[/tex]
Therefore, the final value of k is "8".
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