Question

2. If a spring has a spring constant of 400 N/m, how much elastic potential
energy is stored when the spring is stretched by 0.25 m?​

Answer 1

Answer:

The kinetic energy of a spring is equal to its elastic potential energy.

The elastic potential energy is 12.5N-m or 12.5 Joules.

Explanation:

$= \frac{1}{2} k {x}^{2} \\ = \frac{1}{2} (400)( {.25)}^{2} \\ = 12.5$